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Question Number 26680 by Sr@2004 last updated on 28/Dec/17
(b−c)x^2 +(c−a)x+(a−b)=0 if the   eqation roots  are eqal you proved that  2b=a+c.
(bc)x2+(ca)x+(ab)=0iftheeqationrootsareeqalyouprovedthat2b=a+c.
Answered by mrW1 last updated on 28/Dec/17
equal roots ⇒ Δ=0  Δ=(c−a)^2 −4(b−c)(a−b)=0  ⇒c^2 −2ac+a^2 −4(ab−ac−b^2 +bc)=0  ⇒c^2 +a^2 −4ab+2ac+4b^2 −4bc=0  ⇒(a+c)^2 −4(a+c)b+4b^2 =0  ⇒(a+c−2b)^2 =0  ⇒2b=a+c
equalrootsΔ=0Δ=(ca)24(bc)(ab)=0c22ac+a24(abacb2+bc)=0c2+a24ab+2ac+4b24bc=0(a+c)24(a+c)b+4b2=0(a+c2b)2=02b=a+c

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