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Be-the-vectors-a-1-1-2-b-5-k-k-and-c-3-1-2-in-the-rectangular-Cartesian-coordinate-system-For-any-vector-r-the-equation-r-a-kb-c-has-a-solution-when




Question Number 43613 by indalecioneves last updated on 12/Sep/18
Be the vectors a^→  = (1, −1, 2), b^→  = (−5,  k, k) and c^→  = (3, 1, 2) in the  rectangular Cartesian coordinate system. For any vector r^→ , the equation r^→ ×a^→  + kb^→  = c^→  has a solution when k is equal to?
$${Be}\:{the}\:{vectors}\:\overset{\rightarrow} {{a}}\:=\:\left(\mathrm{1},\:−\mathrm{1},\:\mathrm{2}\right),\:\overset{\rightarrow} {{b}}\:=\:\left(−\mathrm{5},\:\:{k},\:{k}\right)\:{and}\:\overset{\rightarrow} {{c}}\:=\:\left(\mathrm{3},\:\mathrm{1},\:\mathrm{2}\right)\:{in}\:{the} \\ $$$${rectangular}\:{Cartesian}\:{coordinate}\:{system}.\:{For}\:{any}\:{vector}\:\overset{\rightarrow} {{r}},\:{the}\:{equation}\:\overset{\rightarrow} {{r}}×\overset{\rightarrow} {{a}}\:+\:{k}\overset{\rightarrow} {{b}}\:=\:\overset{\rightarrow} {{c}}\:{has}\:{a}\:{solution}\:{when}\:{k}\:{is}\:{equal}\:{to}? \\ $$

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