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bemath-1-x-dy-dx-1-y-1-y-2-ln-x-




Question Number 111330 by bemath last updated on 03/Sep/20
  (√(bemath))   (1/x) (dy/dx) + (1/y) = (1/(y^2  ln (x)))
$$\:\:\sqrt{\mathrm{bemath}} \\ $$$$\:\frac{\mathrm{1}}{\mathrm{x}}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:+\:\frac{\mathrm{1}}{\mathrm{y}}\:=\:\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{2}} \:\mathrm{ln}\:\left(\mathrm{x}\right)} \\ $$

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