Question Number 111330 by bemath last updated on 03/Sep/20
$$\:\:\sqrt{\mathrm{bemath}} \\ $$$$\:\frac{\mathrm{1}}{\mathrm{x}}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:+\:\frac{\mathrm{1}}{\mathrm{y}}\:=\:\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{2}} \:\mathrm{ln}\:\left(\mathrm{x}\right)} \\ $$