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BeMath-Given-2x-2x-6-5y-5y-25-4z-4z-16-and-xy-yz-xz-188-Find-the-solution-




Question Number 108769 by bemath last updated on 19/Aug/20
   ((⋰BeMath⋱)/★)   Given ((2x)/(2x+6)) = ((5y)/(5y+25)) = ((4z)/(4z+16))  and xy + yz + xz = 188 . Find the  solution
\iddotsBeMathGiven2x2x+6=5y5y+25=4z4z+16andxy+yz+xz=188.Findthesolution
Answered by john santu last updated on 19/Aug/20
   ((⊸JS⊸)/♥)  ⇒ (x/(x+3)) = (y/(y+5)) = (z/(z+4))  ⇒ ((x+3)/x) = ((y+5)/y) = ((z+4)/z)  ⇒ (3/x) = (5/y) = (4/z) → { ((y = 5b)),((x = 3b )),((z = 4b)) :}  ⇒15b^2  + 12b^2  + 20b^2  = 188  ⇒47b^2  = 188 ; → { ((b=2)),((b=−2)) :}  case(1) b = 2 →  { ((x=6)),((y=10)),((z=8)) :}  case(2) b=−2 → { ((x=−6)),((y=−10)),((z=−8)) :}
JSxx+3=yy+5=zz+4x+3x=y+5y=z+4z3x=5y=4z{y=5bx=3bz=4b15b2+12b2+20b2=18847b2=188;{b=2b=2case(1)b=2{x=6y=10z=8case(2)b=2{x=6y=10z=8
Commented by bemath last updated on 19/Aug/20
jooss
jooss

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