Question Number 106588 by bemath last updated on 06/Aug/20
$$\:\:\:\:\:\:\:@\mathrm{bemath}@ \\ $$$$\mathrm{x}\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:+\:\mathrm{3x}−\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{e}^{\mathrm{3x}} \: \\ $$