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C-0-pi-2-cos-2-x-4sin-2-x-cos-2-x-dx-




Question Number 178988 by cortano1 last updated on 23/Oct/22
       C = ∫_0 ^(π/2)  ((cos^2 x)/(4sin^2 x+cos^2 x)) dx =?
C=π/20cos2x4sin2x+cos2xdx=?
Answered by qaz last updated on 23/Oct/22
C=∫_0 ^(π/2) ((cos^2 x)/(4sin^2 x+cos^2 x))dx  =∫_0 ^(π/2) ((sec^2 xdx)/((4tan^2 x+1)(1+tan^2 x)))  =∫_0 ^∞ (dx/((4x^2 +1)(1+x^2 )))  =(1/3)∫_0 ^∞ ((4/(1+4x^2 ))−(1/(1+x^2 )))dx  =(2/3)arctan 2x−(1/3)arctan x∣_0 ^∞   =(π/6)
C=0π/2cos2x4sin2x+cos2xdx=0π/2sec2xdx(4tan2x+1)(1+tan2x)=0dx(4x2+1)(1+x2)=130(41+4x211+x2)dx=23arctan2x13arctanx0=π6

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