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calcilate-U-n-0-sin-nx-e-x-1-dx-




Question Number 93636 by abdomathmax last updated on 14/May/20
calcilate U_n =∫_0 ^∞   ((sin(nx))/(e^x −1))dx
$${calcilate}\:{U}_{{n}} =\int_{\mathrm{0}} ^{\infty} \:\:\frac{{sin}\left({nx}\right)}{{e}^{{x}} −\mathrm{1}}{dx} \\ $$$$ \\ $$

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