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Question Number 172989 by SANOGO last updated on 04/Jul/22
calcul: R=+oo   Σ_(n=o) ^(+oo) ((2n)/((2n+1)!))x^n
calcul:R=+oo+oon=o2n(2n+1)!xn
Answered by mr W last updated on 04/Jul/22
sinh x=Σ_(n=0) ^∞ (x^(2n+1) /((2n+1)!))  ((sinh x)/x)=Σ_(n=0) ^∞ (x^(2n) /((2n+1)!))  (((sinh x)/x))′=Σ_(n=0) ^∞ ((2nx^(2n−1) )/((2n+1)!))  x(((sinh x)/x))′=Σ_(n=0) ^∞ ((2nx^(2n) )/((2n+1)!))  cosh x−((sinh x)/x)=Σ_(n=0) ^∞ ((2nx^(2n) )/((2n+1)!))  replace x with (√x)  ⇒cosh (√x)−((sinh (√x))/( (√x)))=Σ_(n=0) ^∞ ((2nx^n )/((2n+1)!))
sinhx=n=0x2n+1(2n+1)!sinhxx=n=0x2n(2n+1)!(sinhxx)=n=02nx2n1(2n+1)!x(sinhxx)=n=02nx2n(2n+1)!coshxsinhxx=n=02nx2n(2n+1)!replacexwithxcoshxsinhxx=n=02nxn(2n+1)!
Commented by Tawa11 last updated on 06/Jul/22
Great sir
Greatsir

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