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Question Number 64159 by mathmax by abdo last updated on 14/Jul/19
calculate  ∫_0 ^1   (dx/(3+2^x ))
calculate01dx3+2x
Commented by turbo msup by abdo last updated on 15/Jul/19
chsngement 2^x =t give e^(xln(2)) =t ⇒  xln(2)=ln(t)⇒x=((ln(t))/(ln2))  ∫_0 ^1  (dx/(3+2^x )) =∫_1 ^2   (dt/(tln2(3+t)))  =(1/(3ln2)) ∫_1 ^2 ((1/t)−(1/(3+t)))dt  =(1/(3ln2))[ln((t/(t+3)))]_1 ^2   =(1/(3ln2)){ln((2/5))−ln((1/4))}  =(1/(3ln2)){ln2−ln5+2ln2}  =(1/(3ln2)){3ln2−ln5}
chsngement2x=tgiveexln(2)=txln(2)=ln(t)x=ln(t)ln201dx3+2x=12dttln2(3+t)=13ln212(1t13+t)dt=13ln2[ln(tt+3)]12=13ln2{ln(25)ln(14)}=13ln2{ln2ln5+2ln2}=13ln2{3ln2ln5}
Answered by Hope last updated on 15/Jul/19
f(x)=(1/(3+2^x ))  f(0)=(1/4)=0.25  f(1)=(1/5)=0.2  ∫_0 ^1 f(x)dx=(1/2)(0.25+0.20)×1=0.225(approx)  Tanmay is hope...
f(x)=13+2xf(0)=14=0.25f(1)=15=0.201f(x)dx=12(0.25+0.20)×1=0.225(approx)Tanmayishope
Commented by Hope last updated on 15/Jul/19
still hope present..i have changed my profile name  because my answer do not get accepted by a[few  so i tried to minimise  my activity in this  platform..0k goodbye
stillhopepresent..ihavechangedmyprofilenamebecausemyanswerdonotgetacceptedbya[fewsoitriedtominimisemyactivityinthisplatform..0kgoodbye
Commented by mathmax by abdo last updated on 15/Jul/19
sir tanmay you are wrong if you say this what s your proof   that your answer is not accepted  you are always actif in that  forum and considered....
sirtanmayyouarewrongifyousaythiswhatsyourproofthatyouranswerisnotacceptedyouarealwaysactifinthatforumandconsidered.

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