calculate-0-4pi-sinx-3-cosx-2-dx-

Question Number 144214 by Mathspace last updated on 23/Jun/21

c a l c u l a t e \int_{0}^{4 π} \frac{s i n x}{{(3 + c o s x)}^{2}} d x

Answered by bemath last updated on 23/Jun/21

= - \underset{0}{\int^{4 π}} \frac{d (3 + \cos x)}{{(3 + \cos x)}^{2}}

= - {[- \frac{1}{3 + \cos x}]}_{0}^{4 π}

= [\frac{1}{3 + \cos 4 π}] - [\frac{1}{3 + \cos 0}] = 0

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