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calculate-0-arctan-2-2t-2-1-t-2-dt-




Question Number 109218 by mathmax by abdo last updated on 22/Aug/20
calculate ∫_0 ^∞  ((arctan(2+2t^2 ))/(1+t^2 ))dt
$$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{arctan}\left(\mathrm{2}+\mathrm{2t}^{\mathrm{2}} \right)}{\mathrm{1}+\mathrm{t}^{\mathrm{2}} }\mathrm{dt} \\ $$

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