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Calculate-0-pi-arctan-2sin-2-x-1-2-2-cos-x-2-2-dx-piarctan-5-1-2-




Question Number 151064 by qaz last updated on 18/Aug/21
Calculate  ::  ∫_0 ^π arctan(((2sin^2 x)/(1−2(√2)ϕcos x+2ϕ^2 )))dx=πarctan (√ϕ)          (ϕ=(((√5)−1)/2))
$$\mathrm{Calculate}\:\:::\:\:\int_{\mathrm{0}} ^{\pi} \mathrm{arctan}\left(\frac{\mathrm{2sin}\:^{\mathrm{2}} \mathrm{x}}{\mathrm{1}−\mathrm{2}\sqrt{\mathrm{2}}\varphi\mathrm{cos}\:\mathrm{x}+\mathrm{2}\varphi^{\mathrm{2}} }\right)\mathrm{dx}=\pi\mathrm{arctan}\:\sqrt{\varphi}\:\:\:\:\:\:\:\:\:\:\left(\varphi=\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{2}}\right) \\ $$

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