Menu Close

calculate-0-pi-sinx-1-cos-2-x-dx-




Question Number 38122 by maxmathsup by imad last updated on 22/Jun/18
calculate  ∫_0 ^π     ((sinx)/( (√(1+cos^2 x))))dx
calculate0πsinx1+cos2xdx
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Jun/18
t=cosx   dt=−sinxdx  ∫_1 ^(−1) ((−dt)/( (√(1+t^2 ))))  ∫_(−1) ^1 (dt/( (√(1+t^2 ))))  l  =∣ln(t+(√(1+t^2 )))∣_(−1) ^1   =ln(1+(√2) )−ln(−1+(√2) )
t=cosxdt=sinxdx11dt1+t211dt1+t2l=∣ln(t+1+t2)11=ln(1+2)ln(1+2)

Leave a Reply

Your email address will not be published. Required fields are marked *