calculate-0-sin-x-6-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 91621 by abdomathmax last updated on 02/May/20 calculate∫0∞sin(x6)dx Commented by mathmax by abdo last updated on 02/May/20 ∫0∞sin(x6)dx=Im(∫0∞eix6dx)wehavebychangementix6=−t⇒x6=it⇒x=(it)16=eiπ12t16⇒∫0∞eix6dx=eiπ12∫0∞e−t×16t16−1dt=16eiπ12∫0∞t16−1e−tdtwehaveΓ(x)=∫0∞tx−1e−tdt=16Γ(16)(cos(π12)+isin(π12))⇒∫0∞sin(x6)dx=16Γ(16)sin(π12) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: hi-every-one-is-it-right-if-we-use-tylor-in-this-integration-and-if-there-were-another-way-that-will-be-very-cool-sin-x-4-dx-Next Next post: a-1-3-2-a-n-1-4a-n-3-3a-n-n-1-a-n- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.