calculate-1-2-x-3-1-x-4-2-dx-

Question Number 40134 by maxmathsup by imad last updated on 16/Jul/18

c a l c u l a t e \int_{1}^{2} \frac{x^{3}}{{(1 + x^{4})}^{2}} d x

Commented by maxmathsup by imad last updated on 18/Jul/18

I = - \frac{1}{4} \int_{1}^{2} \frac{- 4 x^{3}}{{(1 + x^{4})}^{2}} d x = - \frac{1}{4} {[\frac{1}{1 + x^{4}}]}_{1}^{2}

= - \frac{1}{4} {\frac{1}{17} - \frac{1}{2}} \Rightarrow

I = \frac{1}{8} - \frac{1}{68}