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calculate-2x-1-x-2-x-1-3-dx-




Question Number 129867 by Bird last updated on 20/Jan/21
calculate ∫   ((2x−1)/((x^2 −x+1)^3 ))dx
calculate2x1(x2x+1)3dx
Answered by Olaf last updated on 20/Jan/21
Ω = ∫((2x−1)/((x^2 −x+1)^3 ))dx = ∫(du/u^3 )  (u = x^2 −x+1)  Ω = −(1/(2u^2 ))+C = −(1/(2(x^2 −x+1)^2 ))+C
Ω=2x1(x2x+1)3dx=duu3(u=x2x+1)Ω=12u2+C=12(x2x+1)2+C

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