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calculate-3-4-x-2-2x-3-dx-

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Question Number 36418 by abdo.msup.com last updated on 01/Jun/18
calculate ∫_(−3) ^4 ∣x^2 −2x−3∣dx
calculate∫−34∣x2−2x−3∣dx
Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18
x^2 −2x−3 x^2 −3x+x−3 x(x−3)+1(x−3) (x−3)(x+1) critical value of x=−1 and x=3 when x>3 then x^2 −2x−3>0 at x=3 x^2 −2x−3=0 when x<−1 x^2 −2x−3>0 at x=−1 x^2 −2x−3=0 when 3>x>−1 x^2 −2x−3<0 ∫_(−3) ^(−1) x^2 −2x−3 dx+∫_(−1) ^4 −(x^2 −2x−3)dx nw simly solve...
x2−2x−3x2−3x+x−3x(x−3)+1(x−3)(x−3)(x+1)criticalvalueofx=−1andx=3whenx>3thenx2−2x−3>0atx=3x2−2x−3=0whenx<−1x2−2x−3>0atx=−1x2−2x−3=0when3>x>−1x2−2x−3<0∫−3−1x2−2x−3dx+∫−14−(x2−2x−3)dxnwsimlysolve…

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