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calculate-by-recurrence-0-lnx-1-x-n-dx-with-n-2-




Question Number 31060 by abdo imad last updated on 02/Mar/18
calculate by recurrence ∫_0 ^∞    ((lnx)/((1+x)^n ))dx with n≥2 .
calculatebyrecurrence0lnx(1+x)ndxwithn2.

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