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calculate-C-x-y-dxdy-with-C-1-1-1-1-




Question Number 49645 by maxmathsup by imad last updated on 08/Dec/18
calculate ∫∫_C  ∣x+y∣dxdy  with C=[−1,1]×[−1,1]
calculateCx+ydxdywithC=[1,1]×[1,1]
Answered by ajfour last updated on 08/Dec/18
I = 2∫_(−1) ^(  1) [∫_(−x) ^(  1) (x+y)dy]dx     = 2∫_(−1) ^(  1) (xy+(y^2 /2))∣_(−x) ^1 dx     = 2∫_(−1) ^(  1) (x+(1/2)+x^2 −(x^2 /2))dx     = 2∫_0 ^(  1) (x^2 +1)dx = (8/3) .
I=211[x1(x+y)dy]dx=211(xy+y22)x1dx=211(x+12+x2x22)dx=201(x2+1)dx=83.
Commented by maxmathsup by imad last updated on 09/Dec/18
correct answer thanks sir.
correctanswerthankssir.

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