calculate-I-0-1-t-1-4-1-t-3-4-t-dt-

Tinku Tara June 4, 2023 Integration 0 Comments

Question Number 35612 by abdo mathsup 649 cc last updated on 21/May/18

calculate I =∫_0 ^∞ (((1+t)^(−(1/4)) −(1+t)^(−(3/4)) )/t)dt

$${calculate}\:{I}\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{\left(\mathrm{1}+{t}\right)^{−\frac{\mathrm{1}}{\mathrm{4}}} \:\:\:−\left(\mathrm{1}+{t}\right)^{−\frac{\mathrm{3}}{\mathrm{4}}} }{{t}}{dt}\: \\ $$

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