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calculate-I-0-arctan-x-x-3-dx-




Question Number 159592 by mnjuly1970 last updated on 19/Nov/21
     calculate:       I :=∫_0 ^( ∞) (((arctan(x))/x))^3 dx=?
calculate:I:=0(arctan(x)x)3dx=?
Answered by mindispower last updated on 19/Nov/21
byart =(3/2)∫_0 ^∞ ((arctan^2 (x))/(x^2 (1+x^2 )))dx  =3∫_0 ^∞ ((arctan(x))/(x(1+x^2 )))dx−(1/2).((π/2))^3   =3∫_0 ^(π/2) ((xcos(x))/(sin(x)))−(π^3 /(16))  −3∫_0 ^(π/2) ln(sin(x))dx−(π^3 /(16))  ((3π)/2)ln(2)−(π^3 /(16))
byart=320arctan2(x)x2(1+x2)dx=30arctan(x)x(1+x2)dx12.(π2)3=30π2xcos(x)sin(x)π31630π2ln(sin(x))dxπ3163π2ln(2)π316
Commented by mnjuly1970 last updated on 19/Nov/21
thanks alot sir power
thanksalotsirpower
Commented by mindispower last updated on 19/Nov/21
withe pleasur sir
withepleasursir

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