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calculate-I-pi-2-pi-2-ln-1-sinx-dx-




Question Number 34268 by math khazana by abdo last updated on 03/May/18
calculate I = ∫_(−(π/2)) ^(π/2) ln(1+sinx)dx
$${calculate}\:{I}\:=\:\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} {ln}\left(\mathrm{1}+{sinx}\right){dx} \\ $$

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