calculate-lim-n-1-2-3-3-3-n-3-1-2-4-3-4-n-4-

Question Number 38641 by maxmathsup by imad last updated on 27/Jun/18

c a l c u l a t e {l i m}_{n \to + \infty} \frac{1 + 2^{3} + 3^{3} + \dots . + n^{3}}{1 + 2^{4} + 3^{4} + \dots + n^{4}} .

Commented by abdo mathsup 649 cc last updated on 28/Jun/18

t h e Q i s f i n d \sum_{n = 1}^{\infty} \frac{1 + 2^{3} + 3^{3} + \dots + n^{3}}{1 + 2^{4} + 3^{4} + \dots + n^{4}}