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calculate-lim-n-1-e-nx-2-x-2-sin-pi-n-




Question Number 40759 by math khazana by abdo last updated on 27/Jul/18
calculate lim_(n→+∞)      ((1−e^(−nx^2 ) )/(x^2 sin((π/n))))
calculatelimn+1enx2x2sin(πn)
Commented by math khazana by abdo last updated on 27/Jul/18
the Q is find lim_(x→0)    ((1−e^(−nx^2 ) )/(x^2  sin(((πx)/n))))
theQisfindlimx01enx2x2sin(πxn)
Commented by tanmay.chaudhury50@gmail.com last updated on 27/Jul/18
lim_(x→0 )  ((e^(nx^2 ) −1)/(nx^2 ))×(n/e^(nx^2 ) )×(1/({((sin(((Πx)/n)))/((Πx)/n))}))×(1/((Πx)/n))  =1×(n/1)×(1/1)×(n/0)=∞
limx0enx21nx2×nenx2×1{sin(Πxn)Πxn}×1Πxn=1×n1×11×n0=
Answered by tanmay.chaudhury50@gmail.com last updated on 27/Jul/18
lim_(n→∞)   ((1−(1/e^(nx^2 ) ))/(x^2 sin((Π/n))))  when  n→∞  (1/e^(nx^2 ) ) →0   and for any value of  n  the value of sin((Π/n)) lies between ±1          (1/x^2 )>  lim_(n→∞)   ((1−e^(−nx^2 ) )/(x^2 sin((Π/n))))>−(1/x^2 )                        li_(t→0)
limn11enx2x2sin(Πn)whenn1enx20andforanyvalueofnthevalueofsin(Πn)liesbetween±11x2>limn1enx2x2sin(Πn)>1x2lit0

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