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calculate-lim-x-0-1-x-n-cos-x-dx-




Question Number 31675 by gunawan last updated on 12/Mar/18
calculate lim_(x→∞)  ∫_0 ^1 (x^n /(cos x))dx
calculatelimx01xncosxdx
Commented by abdo imad last updated on 12/Mar/18
perhaps there is a error in the Q.how can have 0≤x≤1  and x→+∞ ?...
perhapsthereisaerrorintheQ.howcanhave0x1andx+?
Commented by gunawan last updated on 12/Mar/18
I′m sorry Sir, in written like that
ImsorrySir,inwrittenlikethat
Commented by Joel578 last updated on 13/Mar/18
maybe lim_(n→∞)  ∫_0 ^1  (x^n /(cos x)) dx
maybelimn01xncosxdx
Commented by abdo imad last updated on 13/Mar/18
let use the ch. x^n =t ⇔ x=t^(1/n)   and  A_n =∫_0 ^1   (x^n /(cosx)) dx= ∫_0 ^1   (t/(cos(t^(1/n) ))) (1/n) t^((1/n)−1) dt  =(1/n) ∫_0 ^1     (t^(1/n) /(cos(t^(1/n) )))dt =(1/n) ∫_R   (t^(1/n) /(cos(t^(1/n) ))) χ_([0,1]) (t)dt the  sequence of functions  f_n (t)= (t^(1/n) /(cos(t^(1/n) ))) χ_([0,1]) (t) c.s.to  χ_([0,1]) (t) ⇒ lim_(n→∞)  A_n =lim_(n→∞)  (1/n) ∫_R  χ_([0,1]) (t)dt=0
letusethech.xn=tx=t1nandAn=01xncosxdx=01tcos(t1n)1nt1n1dt=1n01t1ncos(t1n)dt=1nRt1ncos(t1n)χ[0,1](t)dtthesequenceoffunctionsfn(t)=t1ncos(t1n)χ[0,1](t)c.s.toχ[0,1](t)limnAn=limn1nRχ[0,1](t)dt=0

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