calculate-n-0-n-2-2-n- Tinku Tara June 4, 2023 Relation and Functions 0 Comments FacebookTweetPin Question Number 31983 by abdo imad last updated on 17/Mar/18 calculate∑n=0∞n2−2n!. Commented by prakash jain last updated on 18/Mar/18 n2−2=an(n−1)+bn+cc=−2b=1a=1n2−2=n(n−1)+n−2∑∞n=0n2−2n!=∑∞n=0(n(n−1)n!+nn!−2n!)=e+e−2e=0 Commented by abdo imad last updated on 18/Mar/18 ∑n=0∞n2−2n!=∑n=0∞n2n!−2∑n=0∞1n!butwehave∑n=0∞1n!=e∑n=0∞n2n!=∑n=1∞n(n−1)!=∑n=0∞n+1n!=∑n=1∞1(n−1)!+∑n=0∞1n!=∑n=0∞1n!+e=2e⇒∑n=0∞n2−2n!=2e−2e=0. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: let-1-lt-x-lt-1-calculate-n-1-x-n-1-x-n-1-x-n-1-Next Next post: Question-163053 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.