Question Number 41371 by Necxx last updated on 06/Aug/18
$${Calculate}\:{the}\:{amount}\:{of}\:{energy}\circledast \\ $$$${released}\:{when}\:{carbon}-\mathrm{12}\:{nucleus} \\ $$$${is}\:{formed}\:{by}\:{bringing}\:\mathrm{6}\:{neutrons} \\ $$$${and}\:\mathrm{6}\:{protons}\:{together}. \\ $$
Commented by Necxx last updated on 06/Aug/18
$${please}\:{help} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 07/Aug/18
$${let}\:{mass}\:{of}\:{proton}={p} \\ $$$${mass}\:{of}\:{neutron}={n} \\ $$$${mass}\:{of}\:{carbon}−\mathrm{12}\:{nucleus}={c} \\ $$$${energy}\:{released}=\left(\mathrm{6}{p}+\mathrm{6}{n}−{c}\right)×\mathrm{931}{MeV} \\ $$