Calculate-the-density-of-1-mole-of-oxygen-at-a-pressure-of-4-10-4-Nm-2-and-temperature-of-273-2K-

Question Number 42128 by Necxx last updated on 18/Aug/18

C a l c u l a t e t h e d e n s i t y o f 1 m o l e o f

o x y g e n a t a p r e s s u r e o f 4 \times 10^{4} {N m}^{- 2}

a n d t e m p e r a t u r e o f 273.2 K .

Commented by Necxx last updated on 18/Aug/18

p l e a s e c h e c k t h i s a p p r o a c h

n = 1 P = 4 \times 10^{4} N / m^{2} T = 273.2 K

R = 8.31 {J m o l}^{- 1} K^{- 1}

m o l a r m a s s o f o x y g e n = 32 \times 10^{- 3} k g / m o l

m a s s o f 1 m o l e = 3.5 \times 10^{- 26}

∴ V = \frac{n R T}{P} = \frac{1 \times 8.31 \times 273.2}{4 \times 10^{4}} = 5.67 \times 10^{- 2} l

s i n c e d e n s i t y = ρ = m / V t h e n

= \frac{3.5 \times 10^{- 26}}{5.67 \times 10^{- 2}} = 0.617 \times 10^{- 24} k g / l

p l s c h e c k a n d c o m m e n t

Commented by Necxx last updated on 18/Aug/18

p l e a s e h e l p i t s u r g e n t

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