Question Number 31766 by NECx last updated on 14/Mar/18
$${Calculate}\:{the}\:{moment}\:{of}\:{inertia} \\ $$$${of}\:{the}\:{earth}\:{abouth}\:{its}\:{axis}.{If} \\ $$$${the}\:{mass}\:{of}\:{the}\:{earth}\:{is}\:\mathrm{6}.\mathrm{0}×\mathrm{10}^{\mathrm{34}} {kg} \\ $$$${and}\:{radius}\:\mathrm{6}.\mathrm{4}×\mathrm{10}^{\mathrm{6}} {m}. \\ $$$$\left({Assume}\:{the}\:{earth}\:{to}\:{be}\:{a}\:{perfect}\right. \\ $$$$\left.{sphere}\right) \\ $$
Commented by Tinkutara last updated on 14/Mar/18
$$\frac{\mathrm{2}}{\mathrm{5}}{MR}^{\mathrm{2}} =\mathrm{9}.\mathrm{8304}×\mathrm{10}^{\mathrm{47}} \:{kg}\:{m}^{\mathrm{2}} \\ $$