Question Number 14708 by tawa tawa last updated on 03/Jun/17
$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{PH}\:\mathrm{of}\:\:\mathrm{0}.\mathrm{05}\:\mathrm{mol}/\mathrm{dm}^{\mathrm{3}} \:\mathrm{phosporic}\:\mathrm{acid} \\ $$
Answered by Tinkutara last updated on 04/Jun/17
![[H_3 PO_4 ] = 0.05 mol/L ∴ [H^+ ] = 0.15 mol/L pH = −log [H^+ ] ≈ 0.8239 Please confirm the answer. I am not sure!](https://www.tinkutara.com/question/Q14736.png)
$$\left[\mathrm{H}_{\mathrm{3}} \mathrm{PO}_{\mathrm{4}} \right]\:=\:\mathrm{0}.\mathrm{05}\:\mathrm{mol}/\mathrm{L} \\ $$$$\therefore\:\left[\mathrm{H}^{+} \right]\:=\:\mathrm{0}.\mathrm{15}\:\mathrm{mol}/\mathrm{L} \\ $$$$\mathrm{pH}\:=\:−\mathrm{log}\:\left[\mathrm{H}^{+} \right]\:\approx\:\mathrm{0}.\mathrm{8239} \\ $$$$\mathrm{Please}\:\mathrm{confirm}\:\mathrm{the}\:\mathrm{answer}.\:\mathrm{I}\:\mathrm{am}\:\mathrm{not} \\ $$$$\mathrm{sure}! \\ $$
Commented by tawa tawa last updated on 04/Jun/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{it}\:\mathrm{is}\:\mathrm{correct}. \\ $$