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calculste-I-cos-x-n-1-x-2-dx-with-from-R-and-n-integr-natural-2-find-the-vslue-of-cos-3-x-9-1-x-2-dx-




Question Number 39787 by abdo mathsup 649 cc last updated on 10/Jul/18
calculste  I_λ  = ∫_(−∞) ^(+∞)   ((cos(λx^n ))/(1+x^2 )) dx  with  λ from R and n integr natural  2) find the vslue of  ∫_(−∞) ^(+∞)   ((cos(3 x^9 ))/(1+x^2 )) dx .
calculsteIλ=+cos(λxn)1+x2dxwithλfromRandnintegrnatural2)findthevslueof+cos(3x9)1+x2dx.
Commented by abdo mathsup 649 cc last updated on 11/Jul/18
1)  we have I_λ = Re( ∫_(−∞) ^(+∞)   (e^(iλx^n ) /(1+x^2 ))dx)  let  ϕ(z) = (e^(iλz^n ) /(1+z^2 ))  ϕ(z)= (e^(iλz^n ) /((z−i)(z+i))) ⇒  ∫_(−∞) ^(+∞)  ϕ(z)dz =2iπ Res(ϕ,i)  Res(ϕ,i) =lim_(z→i) (z−i)ϕ(z)  =lim_(z→i)  (e^(iλz^n ) /(z+i)) = (e^(λ i^(n+1) ) /(2i)) =(e^(λ{cos((((n+1)π)/2) +isin((((n+1)π)/2))}) /(2i))  ∫_(−∞) ^(+∞)  ϕ(z)dz =2iπ e^(λcos((((n+1)π)/2))) ((cos)(λsin((((n+1)π)/2)))  +isin(λsin((((n+1)π)/2))))/(2i))  ⇒I_λ = π  e^(λ cos((((n+1)π)/2)))  cos{λsin((((n+1)π)/2))} .
1)wehaveIλ=Re(+eiλxn1+x2dx)letφ(z)=eiλzn1+z2φ(z)=eiλzn(zi)(z+i)+φ(z)dz=2iπRes(φ,i)Res(φ,i)=limzi(zi)φ(z)=limzieiλznz+i=eλin+12i=eλ{cos((n+1)π2+isin((n+1)π2)}2i+φ(z)dz=2iπeλcos((n+1)π2)cos)(λsin((n+1)π2))+isin(λsin((n+1)π2))2iIλ=πeλcos((n+1)π2)cos{λsin((n+1)π2)}.
Commented by math khazana by abdo last updated on 12/Jul/18
2) let take λ=3 and n=9 we get  ∫_(−∞) ^(+∞)    ((cos(3x^9 ))/(1+x^2 ))dx =πe^(3cos(5π))  cos{3 sin(5π)}  = π e^(−3)   =(π/e^3 )  .
2)lettakeλ=3andn=9weget+cos(3x9)1+x2dx=πe3cos(5π)cos{3sin(5π)}=πe3=πe3.

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