Question Number 36945 by maxmathsup by imad last updated on 07/Jun/18
$${calulate}\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\:\:\frac{{dx}}{\:\sqrt{{tan}\left({x}\right)\left(\mathrm{1}−{tanx}\right)}} \\ $$
calulate-0-pi-4-dx-tan-x-1-tanx-