Question Number 14042 by RasheedSindhi last updated on 27/May/17
$$\mathrm{Can}\:\mathrm{we}\:\mathrm{express}\:\:\omega^{\mathrm{1}/\mathrm{2}} \:\mathrm{in}\:\mathrm{terms} \\ $$$$\mathrm{of}\:\mathrm{whole}\:\mathrm{powers}\:\mathrm{of}\:\omega? \\ $$
Commented by prakash jain last updated on 27/May/17
$$\sqrt{{w}}=\sqrt{\left(\mathrm{1}\right)\omega}=\sqrt{\omega^{\mathrm{3}} \centerdot\omega}=\sqrt{\omega^{\mathrm{4}} }=\omega^{\mathrm{2}} \\ $$
Commented by RasheedSindhi last updated on 27/May/17
$$\mathcal{T}{hanks}\:{sir}! \\ $$