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CH-3-CH-CH-3-CH-C-C-CH-3-H-2-CH-CH-CH-2-CH-CH-Br-CH-3-what-is-the-iupac-name-




Question Number 164386 by mathls last updated on 16/Jan/22
CH_3 −CH_∣_(CH_3 )  −CH=C^∣^(C^(∣CH_3 ) H_2 )  −CH_∣_(CH_∥_(CH_2 )  )  −CH_∣_Δ  −CH_∣_(Br)  −CH_3       what is the iupac name?
$${CH}_{\mathrm{3}} −{C}\underset{\underset{{CH}_{\mathrm{3}} } {\mid}} {{H}}−{CH}=\overset{\overset{\overset{\mid{CH}_{\mathrm{3}} } {{C}H}_{\mathrm{2}} } {\mid}} {{C}}−{C}\underset{\underset{{C}\underset{\underset{{CH}_{\mathrm{2}} } {\parallel}} {{H}}} {\mid}} {{H}}−{C}\underset{\underset{\Delta} {\mid}} {{H}}−{C}\underset{\underset{{Br}} {\mid}} {{H}}−{CH}_{\mathrm{3}} \:\:\:\: \\ $$$${what}\:{is}\:{the}\:{iupac}\:{name}? \\ $$
Commented by mathls last updated on 16/Jan/22
please help me
$${please}\:{help}\:{me} \\ $$
Commented by mathls last updated on 16/Jan/22
please solve mr W!
$${please}\:{solve}\:{mr}\:{W}! \\ $$
Commented by mathls last updated on 16/Jan/22
who can help me!
$${who}\:{can}\:{help}\:{me}! \\ $$
Commented by mr W last updated on 16/Jan/22
i can′t?
$${i}\:{can}'{t}? \\ $$
Commented by mathls last updated on 16/Jan/22
yes you can because you are the star of  math editor app.
$${yes}\:{you}\:{can}\:{because}\:{you}\:{are}\:{the}\:{star}\:{of} \\ $$$${math}\:{editor}\:{app}. \\ $$
Commented by nikif99 last updated on 16/Jan/22
what means Δ in the 6th atom of C?
$${what}\:{means}\:\Delta\:{in}\:{the}\:\mathrm{6}{th}\:{atom}\:{of}\:{C}? \\ $$
Commented by mr W last updated on 16/Jan/22
you meant with “who can help me!”  “who can help me?”.  so i meant with “i can′t?” “i can′t!”.  that means i didn′t ask if i can, but  said that i really can′t.
$${you}\:{meant}\:{with}\:“{who}\:{can}\:{help}\:{me}!'' \\ $$$$“{who}\:{can}\:{help}\:{me}?''. \\ $$$${so}\:{i}\:{meant}\:{with}\:“{i}\:{can}'{t}?''\:“{i}\:{can}'{t}!''. \\ $$$${that}\:{means}\:{i}\:{didn}'{t}\:{ask}\:{if}\:{i}\:{can},\:{but} \\ $$$${said}\:{that}\:{i}\:{really}\:{can}'{t}. \\ $$
Commented by mathls last updated on 16/Jan/22
it means cyclo propyle
$${it}\:{means}\:{cyclo}\:{propyle} \\ $$

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