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Change-the-following-decimal-number-into-binary-number-73-108-




Question Number 113199 by Rasheed.Sindhi last updated on 11/Sep/20
Change the following decimal  number into binary number:  73.108
Changethefollowingdecimalnumberintobinarynumber:73.108
Commented by bemath last updated on 11/Sep/20
what is binary one sir?
whatisbinaryonesir?
Commented by Rasheed.Sindhi last updated on 11/Sep/20
Read the question now.
Readthequestionnow.
Commented by bemath last updated on 11/Sep/20
ok sir. santuyy
oksir.santuyy
Commented by Rasheed.Sindhi last updated on 11/Sep/20
What′s the meaning of  “santuyy”?
Whatsthemeaningofsantuyy?
Commented by 1549442205PVT last updated on 12/Sep/20
It is counting system of base 2.As I  known ,currently we are using  countimg system of base 10 ,is also  called the decimal system that uses ten   symbols :0,1,...,9 to represent numbers  .The counting system of base 2 is also  called the binary system that uses  only two sumbols 0 and 1 to represent  numbers.It is used in computer  science and digital technology  Converts decimal to binary−odd part  1)Procedure  •Step 1:We multiply the odd part by  a power of 2(say 2^n ,n>1)  •Step 2:get the result in step 1 (only  take whole part)and then convert to  binary  •Step 3:divide the result in step 2 by 2^n   ,we get odd part in binary form  (essentially this step is to move the  comma to the left n times)  2)For example  •Ex1:Convert 2.5625 to binary  2_(10) =10_2   −Multiply :.5625 ∗(2^4 )=9  −Convert 9 to binary:9_(10) =1001_2   −Divide:1001_2 /(2^4 )=.1001  ⇒2.5625_(10) =10.1001_2   •Ex2:Convert 2.3333 to binary  2_(10) =10_2   −Multiply:.3333∗(2^(16) )=21843.1488  −Convert 21843 to binary:  21843_(10) =0101010101010011  −divide 0101010101010011/2^(16)   =.0101010101010011  ⇒2.3333_(10) =10.0101010101010011_2   •Ex3:convert 2.6973 to binary  2_(10) =10_2   −Multiply :.6973 ∗(2^(15) )=22849.1264  −convert 22849 to binary:  22849_(10) =101100101000001_2   −dovide 101100101000001_2 /2^(15)   =.101100101000001_2   ⇒2.6973_(10) =10.101100101000001_2
Itiscountingsystemofbase2.AsIknown,currentlyweareusingcountimgsystemofbase10,isalsocalledthedecimalsystemthatusestensymbols:0,1,,9torepresentnumbers.Thecountingsystemofbase2isalsocalledthebinarysystemthatusesonlytwosumbols0and1torepresentnumbers.ItisusedincomputerscienceanddigitaltechnologyConvertsdecimaltobinaryoddpart1)ProcedureStep1:Wemultiplytheoddpartbyapowerof2(say2n,n>1)Step2:gettheresultinstep1(onlytakewholepart)andthenconverttobinaryStep3:dividetheresultinstep2by2n,wegetoddpartinbinaryform(essentiallythisstepistomovethecommatotheleftntimes)2)ForexampleEx1:Convert2.5625tobinary210=102Multiply:.5625(24)=9Convert9tobinary:910=10012Divide:10012/(24)=.10012.562510=10.10012Ex2:Convert2.3333tobinary210=102Multiply:.3333(216)=21843.1488Convert21843tobinary:2184310=0101010101010011divide0101010101010011/216=.01010101010100112.333310=10.01010101010100112Ex3:convert2.6973tobinary210=102Multiply:.6973(215)=22849.1264convert22849tobinary:2284910=1011001010000012dovide1011001010000012/215=.10110010100000122.697310=10.1011001010000012
Commented by Rasheed.Sindhi last updated on 12/Sep/20
Thanks for detailled answer.
Thanksfordetailledanswer.
Commented by Rasheed.Sindhi last updated on 12/Sep/20
By ′odd part′do you mean  fractional part?(see line#11)
ByoddpartdoyoumeanYou can't use 'macro parameter character #' in math mode
Commented by 1549442205PVT last updated on 12/Sep/20
Ok,is also called decimal part of a  number.Ex:12.34567245 then its  “odd part”is .34567245
Ok,isalsocalleddecimalpartofanumber.Ex:12.34567245thenitsoddpartis.34567245
Answered by Aziztisffola last updated on 11/Sep/20
73.108=73+0.108  (73)_(10) ⇒(x)_2   and (0.108)_(10) ⇒(0.y)_2    ⇒(73.108)_(10) =(x.y)_2   ((73)/2)⇒ q=36 & r=1  ((36)/2)⇒q=18  & r=1  ((18)/2)⇒ q=9 & r=0  (9/2)⇒ q=4 & r=1  (4/2)⇒ q=2 & r=0  (2/2)⇒ q=1 & r=0   (73)_(10) =(1001001)_2 =(x)_2   0.108×2=0.216  1−0.216=0.784  0.784×2=1.568  0.568×2=1.136  0.136×2=0.272  1−0.272=0.728  0.728×2=1.456  0.456×2=0.912  .......  .......  (0.108)_(10) =(0.011010...)_2 =(0.y)_2   then (73.108)_(10) =(1001001.011010...)_2
73.108=73+0.108(73)10(x)2and(0.108)10(0.y)2(73.108)10=(x.y)2732q=36&r=1362q=18&r=1182q=9&r=092q=4&r=142q=2&r=022q=1&r=0(73)10=(1001001)2=(x)20.108×2=0.21610.216=0.7840.784×2=1.5680.568×2=1.1360.136×2=0.27210.272=0.7280.728×2=1.4560.456×2=0.912..(0.108)10=(0.011010)2=(0.y)2then(73.108)10=(1001001.011010)2
Commented by Rasheed.Sindhi last updated on 12/Sep/20
Thanks miss.
Thanksmiss.

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