consider-f-function-Df-0-1-f-0-f-1-c-0-1-2-show-that-f-c-f-c-1-2-

Question Number 164039 by ArielVyny last updated on 13/Jan/22

$$considerffunctionDf=[0,1]$$$$f\left(0\right)=f\left(1\right)c\in [0,\frac{1}{2}]showthatf\left(c\right)=f(c+\frac{1}{2})$$

Answered by Ar Brandon last updated on 13/Jan/22

$$f\left(0\right)=f\left(1\right)$$$$f(c+0)=f(c+1),\mathrm{since}f<1-\mathrm{periodic}$$$$f\left(c\right)=f((c+\frac{1}{2})+\frac{1}{2})=f(c+\frac{1}{2})$$$$\mathrm{Hence}f\left(c\right)=f(c+\frac{1}{2})$$

Commented by Ar Brandon last updated on 13/Jan/22

Thank You M.A������

Commented by Ar Brandon last updated on 13/Jan/22

��Thank You, Sir ����

Commented by Ar Brandon last updated on 13/Jan/22

I just turned 19 today

Commented by Rasheed.Sindhi last updated on 13/Jan/22

Happy birthday to you!

Commented by ArielVyny last updated on 13/Jan/22

$$mybestregardstomisterbrandon$$

Commented by Ar Brandon last updated on 13/Jan/22

Merci bro ��

Commented by amin96 last updated on 13/Jan/22

$$$$happy birthday

Commented by Lordose last updated on 14/Jan/22

$$\mathbf{H}\mathrm{appy}\mathrm{Birthday}\mathrm{Bro}$$

Commented by Lordose last updated on 14/Jan/22

����������

Commented by Ar Brandon last updated on 14/Jan/22

��Thank you! ��

Commented by Ar Brandon last updated on 14/Jan/22

Thank You all , forum friends �� I was 17 when I first entered the forum, and I was so novice. Today thanks to all your teachings I've learned very much. I remain ever grateful ��������

Terms of Service
Privacy Policy
Contact: info@tinkutara.com