Consider-the-sequence-defined-by-0-lt-u-0-lt-1-and-n-N-u-n-1-u-n-u-n-2-1-Show-that-the-sequence-u-n-converges-What-is-its-limit-2-Show-that-the-series-with-general-term-u-n-2-conv

Question Number 127876 by Ar Brandon last updated on 02/Jan/21

$$\mathrm{Consider}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{defined}\:\mathrm{by}:\:\mathrm{0}<\mathrm{u}_{\mathrm{0}} <\mathrm{1}\:\mathrm{and}\:\forall\mathrm{n}\in\mathbb{N},\:\mathrm{u}_{\mathrm{n}+\mathrm{1}} =\mathrm{u}_{\mathrm{n}} −\mathrm{u}_{\mathrm{n}} ^{\mathrm{2}} . \\ $$$$\mathrm{1}.\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sequence}\:\left(\mathrm{u}_{\mathrm{n}} \right)\:\mathrm{converges}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{its}\:\mathrm{limit}\:? \\ $$$$\mathrm{2}.\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{series}\:\mathrm{with}\:\mathrm{general}\:\mathrm{term}\:\mathrm{u}_{\mathrm{n}} ^{\mathrm{2}} \:\mathrm{converges}. \\ $$$$\mathrm{3}.\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{series}\:\mathrm{with}\:\mathrm{general}\:\mathrm{terms}\:\mathrm{ln}\left(\frac{\mathrm{u}_{\mathrm{n}+\mathrm{1}} }{\mathrm{u}_{\mathrm{n}} }\right)\:\mathrm{and}\:\mathrm{u}_{\mathrm{n}} \:\mathrm{diverge}. \\ $$

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