Question Number 57001 by nisha sinah last updated on 28/Mar/19
$${construct}\:{an}\:{analytic}\:{function}\:{f}\left({z}\right)\:{whose}\:{real}\:{part}\:{is}\:{e}^{{x}} \mathrm{cos}\:{y} \\ $$
Commented by 121194 last updated on 28/Mar/19
$${f}\left({z}\right)={e}^{{z}} \\ $$$${e}^{{z}} ={e}^{{x}+{iy}} ={e}^{{x}} \mathrm{cos}\:{y}+{ie}^{{x}} \mathrm{sin}\:{y} \\ $$