Question Number 19405 by $@ty@m last updated on 10/Aug/17
$${Convert}\:{i}\sqrt{\frac{\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{1}}{\mathrm{2}}}\:{into}\:{polarform}. \\ $$
Answered by Tinkutara last updated on 10/Aug/17
$$\sqrt{\frac{\mathrm{2}\sqrt{\mathrm{2}}\:−\:\mathrm{1}}{\mathrm{2}}}\left(\mathrm{cos}\:\frac{\pi}{\mathrm{2}}\:+\:{i}\:\mathrm{sin}\:\frac{\pi}{\mathrm{2}}\right) \\ $$
Commented by $@ty@m last updated on 11/Aug/17
$${Thank}\:{youSir} \\ $$