Correction-to-the-last-assignment-1-1-81-x-2-27-1-x-1-3-4-x-2-3-3-1-x-1-3-4x-8-3-3-3x-3-4x-8-3-3-3x-4x-8-3-3x-C-L-T-4x-3x-3-8-x-5-x-5-2-9-x-1-729-9-x-

Question Number 120241 by olalekanoriyomi last updated on 30/Oct/20

C o r r e c t i o n t o t h e l a s t a s s i g n m e n t

(1) \frac{1}{81^{x - 2}} = 27^{1 - x}

\frac{1}{3^{4 (x - 2)}} = 3^{3 (1 - x)}

\frac{1}{3^{4 x - 8}} = 3^{3 - 3 x}

3^{- 4 x + 8} = 3^{3 - 3 x}

- 4 x + 8 = 3 - 3 x

C . L . T

- 4 x + 3 x = 3 - 8

- x = - 5

x = 5

(2) 9^{x} = \frac{1}{729}

9^{x} = \frac{1}{3^{6}}

3^{2 x} = 3^{- 6}

2 x = - 6

x = \frac{- 6}{2}

x = - 3

(3) 16^{x} = 0.125

2^{4 x} = \frac{125}{1000}

2^{4 x} = \frac{1}{8}

2^{4 x} = 2^{- 3}

4 x = - 3

x = \frac{- 3}{4}

(4) a^{1 / 2} = 4

a =