Menu Close

cos-1-sin-41-sin-19-3-4-




Question Number 149259 by john_santu last updated on 04/Aug/21
 cos^(−1) ((√(sin (41°)sin (19°)+(3/4))) )=?
cos1(sin(41°)sin(19°)+34)=?
Answered by john_santu last updated on 04/Aug/21
⇔sin 41°sin 19°=((−2sin 4l°sin 19°)/(−2))  =((cos 60°−cos 22°)/(−2))=((cos 22°−(1/2))/2)  =(1/2)cos 22°−(1/4)  ⇒cos^(−1) ((√((1/2)cos 22°+(1/2))) )=  cos^(−1) ((√((1/2)(2cos^2 11°−1+1))))  cos^(−1) ((√(cos^2 11°)))=cos^(−1) (cos 11°)  = 11°
sin41°sin19°=2sin4l°sin19°2=cos60°cos22°2=cos22°122=12cos22°14cos1(12cos22°+12)=cos1(12(2cos211°1+1))cos1(cos211°)=cos1(cos11°)=11°

Leave a Reply

Your email address will not be published. Required fields are marked *