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cos-2-3-sin-pi-2-3sin-2-7pi-2-2cos-5pi-




Question Number 164757 by mathlove last updated on 21/Jan/22
cos α=(2/3)  sin((π/2)+α)−3sin^2 (((7π)/2)+α)−2cos(5π+α)=?
cosα=23sin(π2+α)3sin2(7π2+α)2cos(5π+α)=?
Commented by blackmamba last updated on 21/Jan/22
⇒=cos α−3cos^2 α+2cos α  ⇒=3×(2/3)−3×(4/9)  ⇒=((6−4)/3)=(2/3)
⇒=cosα3cos2α+2cosα⇒=3×233×49⇒=643=23

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