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cos25-sin65-sin20-sin10-




Question Number 164483 by mathlove last updated on 18/Jan/22
((cos25−sin65)/(sin20+sin10))=?
$$\frac{{cos}\mathrm{25}−{sin}\mathrm{65}}{{sin}\mathrm{20}+{sin}\mathrm{10}}=? \\ $$
Commented by som(math1967) last updated on 18/Jan/22
0
$$\mathrm{0} \\ $$
Answered by Rasheed.Sindhi last updated on 18/Jan/22
((cos25−sin65)/(sin20+sin10))  =((sin(90−25)−sin65)/(sin20+sin10))  =((sin65−sin65)/(sin20+sin10))  =(0/(sin20+sin10))=0
$$\frac{{cos}\mathrm{25}−{sin}\mathrm{65}}{{sin}\mathrm{20}+{sin}\mathrm{10}} \\ $$$$=\frac{{sin}\left(\mathrm{90}−\mathrm{25}\right)−{sin}\mathrm{65}}{{sin}\mathrm{20}+{sin}\mathrm{10}} \\ $$$$=\frac{{sin}\mathrm{65}−{sin}\mathrm{65}}{{sin}\mathrm{20}+{sin}\mathrm{10}} \\ $$$$=\frac{\mathrm{0}}{{sin}\mathrm{20}+{sin}\mathrm{10}}=\mathrm{0}\: \\ $$$$ \\ $$

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