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cosec-2-67-0-tan-2-23-0-




Question Number 21280 by gopikrishnan005@gmail.com last updated on 18/Sep/17
cosec^2 67^0 −tan^2 23^0 =
$${cosec}^{\mathrm{2}} \mathrm{67}^{\mathrm{0}} −{tan}^{\mathrm{2}} \mathrm{23}^{\mathrm{0}} = \\ $$
Answered by $@ty@m last updated on 18/Sep/17
1
$$\mathrm{1} \\ $$

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