cosec-4x-2-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 25209 by Mr eaay last updated on 06/Dec/17 ∫cosec4x2dx Answered by prakash jain last updated on 06/Dec/17 =∫cosec2xdx=∫12sinxcosxdx=12∫1sin2x(cosxsinx)dx=12∫cosec2xcotxdx=−12ln(cotx)+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-25203Next Next post: solve-t-1-3-t-1-2-12- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.