cosxcos-pi-6-sin-pi-6-sinx-pi-4-

Question Number 167986 by DAVONG last updated on 31/Mar/22

cosxcos \frac{π}{6} - \sin \frac{π}{6} sinx = \frac{π}{4}

Answered by Rasheed.Sindhi last updated on 31/Mar/22

cosxcos \frac{π}{6} - \sin \frac{π}{6} sinx = \frac{π}{4}

\Rightarrow \cos (x + \frac{π}{6}) = \frac{π}{4}

x + \frac{π}{6} = \cos^{- 1} (\frac{π}{4})

x = \cos^{- 1} (\frac{π}{4}) - \frac{π}{6}

∙ x = \cos^{- 1} (\frac{π}{4}) + 2 n π - \frac{π}{6}

∙ x = \cos^{- 1} (2 π - \frac{π}{4}) + 2 n π - \frac{π}{6}

= \cos^{- 1} (\frac{7 π}{4}) + 2 n π - \frac{π}{6}