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cot-2-x-cot-4-x-dx-

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Question Number 79500 by ubaydulla last updated on 25/Jan/20
∫(cot^2 x+cot^4 x)dx
∫(cot2x+cot4x)dx
Answered by john santu last updated on 25/Jan/20
∫cot^2 x(1+cot^2 x)dx = ∫cot^2 x cosec^2 xdx= ∫−cot^2 x d(cot x) = −(1/3)cot^3 x + c
∫cot2x(1+cot2x)dx=∫cot2xcosec2xdx=∫−cot2xd(cotx)=−13cot3x+c

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