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cot-x-ln-sin-x-dx-




Question Number 125965 by bramlexs22 last updated on 16/Dec/20
    ∫ cot x ln (sin x) dx ?
cotxln(sinx)dx?
Answered by Lordose last updated on 16/Dec/20
  ∫cot(x)ln(sin(x))dx =^(u=ln(sin(x))) ∫udu     = (u^2 /2) + C = ((ln^2 sin(x))/2) + C
cot(x)ln(sin(x))dx=u=ln(sin(x))udu=u22+C=ln2sin(x)2+C

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