Question Number 94084 by seedhamaieng@gmail.com last updated on 16/May/20
$$\int\sqrt{\mathrm{cot}{x}}{dx}\: \\ $$
Commented by Kunal12588 last updated on 16/May/20
$$=\int\sqrt{{tan}\left(\pi/\mathrm{2}−{x}\right)}\:{dx} \\ $$$$=−\int\sqrt{{tan}\:{t}}\:{dt}\:;\:{with}\:{t}={tan}\left(\frac{\pi}{\mathrm{2}}−{x}\right) \\ $$$$\int\sqrt{{tan}\:{x}}\:{dx}\:{is}\:{very}\:{popular}\:{integral},\:{its}\:{already} \\ $$$${answered}\:{here}\:;\:{maybe}\:{you}\:{have}\:{to}\:{dig}\:{deeper} \\ $$$${or}\:{search}\:{in}\:{The}\:{Internet}. \\ $$
Commented by M±th+et+s last updated on 16/May/20
$${go}\:{to}\:{Q}.\mathrm{99340}\: \\ $$