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covert-the-point-p-4-3-pi-6-pi-3-to-cartesian-coordinates-




Question Number 94589 by  M±th+et+s last updated on 19/May/20
covert the point(p,θ,ϕ)=[4(√3),(π/6),(π/3)]   to cartesian coordinates.
$${covert}\:{the}\:{point}\left({p},\theta,\varphi\right)=\left[\mathrm{4}\sqrt{\mathrm{3}},\frac{\pi}{\mathrm{6}},\frac{\pi}{\mathrm{3}}\right]\: \\ $$$${to}\:{cartesian}\:{coordinates}. \\ $$
Commented by mr W last updated on 19/May/20
Commented by mr W last updated on 19/May/20

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